Integrand size = 22, antiderivative size = 44 \[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=-\frac {(a+b x)^{-1+m} \operatorname {Hypergeometric2F1}\left (2,-1+m,m,\frac {a+b x}{2 a}\right )}{4 a^2 b (1-m)} \]
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Time = 0.01 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {641, 70} \[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=-\frac {(a+b x)^{m-1} \operatorname {Hypergeometric2F1}\left (2,m-1,m,\frac {a+b x}{2 a}\right )}{4 a^2 b (1-m)} \]
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Rule 70
Rule 641
Rubi steps \begin{align*} \text {integral}& = \int \frac {(a+b x)^{-2+m}}{(a-b x)^2} \, dx \\ & = -\frac {(a+b x)^{-1+m} \, _2F_1\left (2,-1+m;m;\frac {a+b x}{2 a}\right )}{4 a^2 b (1-m)} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(102\) vs. \(2(44)=88\).
Time = 0.34 (sec) , antiderivative size = 102, normalized size of antiderivative = 2.32 \[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=\frac {(a+b x)^m \left (4 a \left (\frac {1}{m}+\frac {a}{(-1+m) (a+b x)}\right )+\frac {2 (a+b x) \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {a+b x}{2 a}\right )}{1+m}+\frac {(a+b x) \operatorname {Hypergeometric2F1}\left (2,1+m,2+m,\frac {a+b x}{2 a}\right )}{1+m}\right )}{16 a^4 b} \]
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\[\int \frac {\left (b x +a \right )^{m}}{\left (-b^{2} x^{2}+a^{2}\right )^{2}}d x\]
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\[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=\int { \frac {{\left (b x + a\right )}^{m}}{{\left (b^{2} x^{2} - a^{2}\right )}^{2}} \,d x } \]
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\[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=\int \frac {\left (a + b x\right )^{m}}{\left (- a + b x\right )^{2} \left (a + b x\right )^{2}}\, dx \]
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\[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=\int { \frac {{\left (b x + a\right )}^{m}}{{\left (b^{2} x^{2} - a^{2}\right )}^{2}} \,d x } \]
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\[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=\int { \frac {{\left (b x + a\right )}^{m}}{{\left (b^{2} x^{2} - a^{2}\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {(a+b x)^m}{\left (a^2-b^2 x^2\right )^2} \, dx=\int \frac {{\left (a+b\,x\right )}^m}{{\left (a^2-b^2\,x^2\right )}^2} \,d x \]
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